If a solution requires 5 mL of saline for every 8 mL of medicine, how much saline is required for 45 mL of medicine?

If a solution requires 5 mL of saline for every 8 mL of medicine, how much saline is required for 45 mL of medicine?

• A. 225 mL
• B. 22.5 mL
• C. 225/8 mL
• D. 50 mL

Answer: (C)

To determine how much saline is required for 45 mL of medicine based on the ratio given, we can start by defining the relationship between saline and medicine from the information provided: 5 mL of saline is needed for every 8 mL of medicine. Using this ratio, we can set up a proportion to find the required saline for the 45 mL of medicine: \[ \frac{\text{saline}}{\text{medicine}} = \frac{5 \text{ mL saline}}{8 \text{ mL medicine}} \] Let \( x \) be the amount of saline needed for 45 mL of medicine. We can express this relationship as: \[ \frac{x}{45} = \frac{5}{8} \] Cross-multiplying to solve for \( x \) gives us: \[ 8x = 5 \times 45 \] Calculating the right-hand side: \[ 5 \times 45 = 225 \] So we have: \[ 8x = 225 \] Dividing both sides by 8 to isolate \( x \): \[ x = \frac{225}{8} \] Thus,

To determine how much saline is required for 45 mL of medicine based on the ratio given, we can start by defining the relationship between saline and medicine from the information provided: 5 mL of saline is needed for every 8 mL of medicine.

Using this ratio, we can set up a proportion to find the required saline for the 45 mL of medicine:

[

\frac{\text{saline}}{\text{medicine}} = \frac{5 \text{ mL saline}}{8 \text{ mL medicine}}

]

Let ( x ) be the amount of saline needed for 45 mL of medicine. We can express this relationship as:

[

\frac{x}{45} = \frac{5}{8}

]

Cross-multiplying to solve for ( x ) gives us:

[

8x = 5 \times 45

]

Calculating the right-hand side:

[

5 \times 45 = 225

]

So we have:

[

8x = 225

]

Dividing both sides by 8 to isolate ( x ):

[

x = \frac{225}{8}

]

Thus,