If Danny takes 48 minutes to walk 3 miles, how long should it take him to walk 5 miles maintaining the same speed?

If Danny takes 48 minutes to walk 3 miles, how long should it take him to walk 5 miles maintaining the same speed?

• A. 60 minutes
• B. 80 minutes
• C. 90 minutes
• D. 75 minutes

Answer: (B)

To determine how long it will take Danny to walk 5 miles at the same speed, we start by calculating his speed based on the information given. Danny takes 48 minutes to walk 3 miles. First, we find his walking speed in miles per minute: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} = \frac{3 \text{ miles}}{48 \text{ minutes}} = \frac{1}{16} \text{ miles per minute} \] Now, to find out how long it will take him to walk 5 miles at this speed, we use the formula: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \] Substituting in the values for distance and speed: \[ \text{Time} = \frac{5 \text{ miles}}{\frac{1}{16} \text{ miles per minute}} = 5 \times 16 = 80 \text{ minutes} \] This calculation shows that it will take Danny 80 minutes to walk 5 miles if he maintains the same walking speed. Therefore, this is the correct time based on the constant speed derived

To determine how long it will take Danny to walk 5 miles at the same speed, we start by calculating his speed based on the information given. Danny takes 48 minutes to walk 3 miles.

First, we find his walking speed in miles per minute:

[

\text{Speed} = \frac{\text{Distance}}{\text{Time}} = \frac{3 \text{ miles}}{48 \text{ minutes}} = \frac{1}{16} \text{ miles per minute}

]

Now, to find out how long it will take him to walk 5 miles at this speed, we use the formula:

[

\text{Time} = \frac{\text{Distance}}{\text{Speed}}

]

Substituting in the values for distance and speed:

[

\text{Time} = \frac{5 \text{ miles}}{\frac{1}{16} \text{ miles per minute}} = 5 \times 16 = 80 \text{ minutes}

]

This calculation shows that it will take Danny 80 minutes to walk 5 miles if he maintains the same walking speed. Therefore, this is the correct time based on the constant speed derived